Anyone know how to do this or has the answer?? Much appreciated ☺️

$200

Step-by-step explanation:

For this one, you want to make algebraic equations. In this case, they would be r+7v=120 and r+10v=150 (where r is the register fee and v is the cost of a visit).

To solve simultaneous equations with a like term (when they have the same sign in front), you can solve by subtracting one equation from the other. This gives (r-r)+(10v-7v)=(150-120) or 3v=30, which can be solved to v=10.

To work out r, we can sub the known value of v (10) for v in either equation. This gives r+(10×10)=150 or r+100=150. This can be solved to r=50.

This makes the expression c=50+10n (where c is the total cost and n is the number of visits.

Lisa went 15 times, so this becomes c=50+(10×15) or c=50+150, which gives c=200.

**This content involves writing and solving simultaneous equations from worded questions, which you may wish to revise. I'm always happy to help!

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.

alright well the answers to your question is

2xy/9 hope this have a nice day : )

step-by-step explanation: