What is the area of a regular pentagon with a side of 10 in.? Round the answer to the nearest tenth.
96.3in^2
172.0in^2
344.1in^2
192.6in^2
DONT RESPOND WITH A LINK

A = 172.0 in²

Step-by-step explanation:

Exterior angle of any side is 360 / 5 = 72°

Interior angle between any two adjacent sides is 180 - 72 = 108°

A regular pentagon can be thought of as 5 isosceles triangles with two common angles of 108 / 2 = 54°

The height of each triangle is

h = (10/2)tan54

The area of each triangle is ½(10)h = ½(10)(10/2)tan54 = 25tan54

The area of the pentagon is

A = 5(25tan54) = 125tan54 = 172.04774005...

A = 172.0 in²

let x be the money she spent so that she can earn the free t-shirt.

since, she already spent $112.49

⇒

also, as per the statement: jennifer must spend $250 or more in order to qualify for a free t-shirt at the store.

then,

we have an inequality i.,e

subtract 112.49 from both sides we get;

therefore, $137. 51 more money does jennifer need to spend so that she can earn the free t-shirt