Find the intersection of the lines y = x +1 and 3y + 2x = 13 without drawing the graph.

The intersection point is (2, 3)

Step-by-step explanation:

The given (linear) equations for the point of intersection is required are;

y = x + 1...(1)

3·y + 2·x = 13...(2)

To find the point of intersection without using graph, we note that the point of intersection is the point at which the values of both equations are equal

We find the values of 'x' and y-coordinates at the point of intersection as follows;

Making 'y' the subject of equation (2) gives;

y = (13 - 2·x)/3

When both lines intersect, the 'x' and y-values are the same;

y = x + 1 for the first line, and y = (13 - 2·x)/3 for the second line, therefore, at the intersection point, we have;

y = y

x + 1 = (13 - 2·x)/3

3·(x + 1) = 13 - 2·x

3·x + 3 = 13 - 2·x

3·x + 2·x = 13 - 3

3·x + 2·x = 5·x = 13 - 3 = 10

∴ 5·x = 10

Therefore, at the point of intersection, x = 10/5 = 2

x = 2

'y' is given in equation (1) by y = x + 1, therefore, at the point of intersection, 'x = 2', we get;

y = x + 1

∴ The value of 'y' at the point of intersection is y = 2 + 1 = 3

y = 3

Therefore, the (x, y) coordinate at the point of intersection is (2, 3) which can be written as follows;

The point of intersection = (2, 3).

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step-by-step explanation:

the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

now, we can solve for w

subtract both sides by 12

divide both sides by 2

and we get

so,

the smallest possible measurement of the width is 14 feet