Find the simplified product: ^3 square root of 9x^4 * ^3 square root of 3x^8

Step-by-step explanation:

multiply

9 times 3 is 27

x to the fourth times x to the eighth is x to the twelfth

this all under the cube root so I know that is the square root but pretend that it is the cube root of it

The cube root of 27 is 3 and the cube root of x to the twelfth is x to the fourth

so you have 3 times x to the fourth or

i = 2 / - 5

step-by-step explanation:

evaluation of ( 2 - 4 ) ( p + q ) when p = 2 and q = 5 i, by putting values of p and q,                                                                    

sorry i got nothing

step-by-step explanation: