if the angle of elevation of the sun is 40 degrees, and is decreasing 1/3 radians/hour how fast is the shadow of a 35m tall pole lengthening?

Step-by-step explanation:

Let y = height of the pole = 35 m (constant)

x = length of the shadow

They are related as

or

Taking the time derivative of the above expression and keeping in mind that y is constant, we get

Before we plug in the numbers, let's convert the degree unit into radians:

Since the angle is decreasing, then d(theta)/dt is negative. Therefore, the rate at which the shadow is lengthening is

or

step-by-step explanation:

a rhombus is a parallelogram enjoying his symmetry.

1.3 million hoops i believe