The graph of y=4x2-4x-1=0

Here we have the equation:

y = 4*x^2 - 4*x - 1

And we should have the graph (you can see it below this answer)

Now we want to find the solutions of:

4*x^2 - 4*x - 1 = 0

These solutions will be the two values of x at which the graph of our function intersects the line y = 0, that is the x-axis.

Then we need to find the two values of x at which our graph intersects the x-axis.

In the graph, we can estimate the solutions as:

x = -0.2

x = 1.2

To find the exact solutions we can use the Bhaskara's equation, and we will find that the solutions are given by:

Then the two solutions are:

x = (4 + 5.66)/8 = 11.2075

x = (4 - 5.66)/8 = -0.2075

Step-by-step explanation:

the answer is the option b

the range is all real numbers

step-by-step explanation:

we know that

the absolute value parent function is equal to

see the attached figure to better understand the problem

so

a. it is v-shaped > is true

b. the range is all real numbers > is not true

because the range is the > [0,∞)

all real numbers greater than or equal to zero

c. it goes through the origin > is true

d. the domain is all real numbers > is true

step-by-step explanation: