see attachment :)) I've been stuck on this question forever... I do not understand how they got 2r^2-60r-45=0. I know the formula for the area of the circle is r^2 pi... but still... Can someone answer the question with explanation?

2r² - 60r - 45 = 0

Step-by-step explanation:

Hang on this is going to be convoluted

Area of pond

a = πr²

Area of path

a = πr²/10

Combined Area

a = πr² + πr²/10

a = π(r² + r²/10)

The Combined Area can also be expressed as

a = π(r + 1.5)²

a = π(r² + 3r + 2.25)

Set the areas equal

π(r² + r²/10) = π(r² + 3r + 2.25)

Divide both sides by π

r² + r²/10 = r² + 3r + 2.25

Subtract r² from both sides

r²/10 = 3r + 2.25

Multiply both sides by 20

2r² = 60r + 45

Subtract 60r + 45 from both sides

2r² - 60r - 45 = 0

answer: standard form is ax^2 + bx + c = 0

step-by-step explanation:

standard form is ax^2 + bx + c = 0

(2x + 1)(x - 2) = 0

distribute to get into standard form

2x^2 - 4x + x - 2 = 0

2x^2 - 3x - 2 = 0

a = 2, b= -3, c = -2

a is your answer

answer:   c ?

step-by-step explanation: