You have one type of nut that sells for $1.80/lb and another type of nut that sells for $8.00/lb. You would like to have 18.6 lbs of a nut mixture that sells for $3.30/lb. How much of each nut will you need to obtain
the desired mixture?
You will need
lbs of the cheaper nut
and
lbs of the expensive nut.

what are the things "represented below"?

step-by-step explanation:

nobody can if you dont give the choices

b.-4 units

all you   do is count how many times you move

85.560%

step-by-step explanation:

conditional probability is defined as:

p(a|b) = p(a∩b) / p(b)

in other words, the probability that a occurs, given that b has occurred = the probability that both a and b occur / the probability that b occurs.

in this example:

p(turns 64 | turns 44) = p(turns 64 & turns 44) / p(turns 44).

if someone turns 64, they must have already turned 44, so:

p(turns 64 | turns 44) = p(turns 64) / p(turns 44)

on page 42, we see that of the original 100,000, 94944 turn 44, and 81234 turn 64.   therefore:

p(turns 64 | turns 44) = 81234 / 94944

p(turns 64 | turns 44) = 0.85560