Yasmin has a bag containing 165 colored beads. Her classmates take turns selecting one bead from the bag without looking, recording the color in the table, and replacing the bead. If the bag contained an equal number of each color of bead, for which color is the experimental probability closest to the theoretical probability?

Step-by-step explanation:

The record of experiment are as follows:

Color                    Red            Brown       Orange  Yellow

Number of Beads     10           15              17      13

Total number of beads recorded=10+15+17+13=55 beads

Also, the Probability of Red bead is=10/55

Probability of Brown bead is=15/55

Probability of Orange bead is=17/55

Probability of Yellow bead is=13/55

Number of red beads in Yasmin's bag are:

\dfrac{10}{55}\times 165=305510×165=30

Number of brown beads in Yasmin's bag are:

\dfrac{15}{55}\times 165=455515×165=45

Number of orange beads in Yasmin's bag are:

\dfrac{17}{55}\times 165=515517×165=51

Number of yellow beads in Yasmin's bag are:

\dfrac{13}{55}\times 165=395513×165=39

mark other person brainliest

let's add {f(x)=x+1}f(x)=x+1 and {g(x)=2x}g(x)=2x together to make a new function.

f(x)+g(x) =(x+1)+(2x)=x+1+2x=3x+1

let's call this new function hh. so we have:

{h(x)}={f(x)}+{g(x)}{=3x+1}h(x)=f(x)+g(x)=3x+1

we can also evaluate combined functions for particular inputs. let's evaluate function hh above for x=2x=2. below are two ways of doing this.

method 1: substitute x=2x=2 into the combined function hh.

h(x)

h(2)

​    

=3x+1

=3(2)+1

=7

​ since h(x)=f(x)+g(x)h(x)=f(x)+g(x), we can also find h(2)h(2) by finding f(2) +g(2)f(2)+g(2).

first, let's find f(2)f(2):

f(x)

f(2)

​    

=x+1

=2+1

=3

​  

now, let's find g(2)g(2):

g(x)

g(2)

​    

=2x

=2⋅2

=4

​  

so f(2)+g(2)=3+4=\greend7f(2)+g(2)=3+4=7.

notice that substituting x =2x=2 directly into function hh and finding f(2) + g(2)f(2)+g(2) gave us the same answer!