Which is the slopc-intercept form of the equation of a line that is perpendicular to
the line y = 2r – 7 and passes through the
point (-5, 6)?

Step-by-step explanation:

Hi there!

What we need to know:

1) Determine the slope (m)

From the given equation, we can identify clearly that 2 is in the place of m, making it the slope. The negative reciprocal of 2 is -1/2, so therefore, the slope of a perpendicular line would be -1/2. Plug this into :

2) Determine the y-intercept (b)

Plug in the given point (-5,6) and solve for b

Subtract 5/2 from both sides to isolate b

Therefore, the y-intercept of the line is . Plug this back into :

I hope this helps!

answer: group b.

step-by-step explanation:

the polynomial is a perfect square trinomial of the form a^2-2ab+b^2:

option a. true

step-by-step explanation:

9x^2-12x+4

comparing with the form a^2-2ab+b^2

1.) a^2=9x^2

solving for a: square root both sides of the equation:

sqrt(a^2)=sqrt(9x^2)

a=sqrt(9) sqrt(x^2)

a=3x

2.) b^2=4

solving for b: square root both sides of the equation:

sqrt(b^2)=sqrt(4)

b=2

to be a perfet square trinomial 2ab must be equal to 12x. let's check:

2ab = 2 (3x) (2)

2ab = 12x

correct