Find the H. C.F of the following. (a)2x,3y
(b)6a,5b
(c)30xy,35yz
(d)12a,30b,45ab²
(e)p²q, pq³,pq4
(f)7x²,21xy²,xy
(g)5x²,15y³,10xy²
(h)2x,3y,11z
(i)5a,6b,7c

1

1

5y

2

pq

x

1

1

hope that helps !!!

the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

now, we can solve for w

subtract both sides by 12

divide both sides by 2

and we get

so,

the smallest possible measurement of the width is 14 feet