I have to use completing the square then put it in vertex form, and I have no clue how the hell do to that.

y=8(x+1)²-2

Step-by-step explanation:

Completing the square is a method of factorising. x²+bx+c=0 becomes x²+bx+(b)²-(b)²+c=0. This then gets converted to make an equation of (x+b)²+(-(b)²+c)=0.

Vertex form is y=a(x-h)²+k.

8x²+16x+6=0 must first be divided by 8 to 8(x²+2x+)=0 (as there cannot be a coefficient for x²).

This will become 8(x²+2x+²-²+)=0.

From there, using the method above, we can convert it to 8[(x+1)²-1+]=0.

Solving this gets 8[(x+1)²-]=0.

With 8 as a, 1 as -h, and 8×- (-2) as k, we can input this into vertex format to get the result of y=8(x+1)²-2.

**This equation involves completing the square and vertex form, which you may wish to revise. I'm always happy to help!

a4 - 3a2 - 1

step-by-step explanation:

step   1   :

equation at the end of step   1   :

  ((a4) -   3a2) -   1

step   2   :

trying to factor by splitting the middle term

2.1     factoring   a4-3a2-1  

the first term is,   a4   its coefficient is   1 .

the middle term is,   -3a2   its coefficient is   -3 .

the last term, "the constant", is   -1  

$5.41

step-by-step explanation:

$20 - $14.51 = $5.49.