Find the area if the composite shape

111 m²

Step-by-step explanation:

A rectangle is a quadrilateral (has four sides and four angle) with two pairs of parallel sides. Opposite sides of a rectangle are equal to each other. Also all the angles of a rectangle are 90° each.

The area of a rectangle = length * width

For rectangle 1, length = 12 m, width = 3 m

Therefore area of rectangle 1 = length * width = 12 m * 3 m = 36 m²

For rectangle 2, length =(12 m - 3 m - 3 m) = 6 m, width =(15 m - 10 m) =5 m

Therefore area of rectangle 2 = length * width = 6 m * 5 m = 30 m²

For rectangle 3, length = 15 m, width = 3 m

Therefore area of rectangle 3 = length * width = 15 m * 3 m = 45 m²

Area of composite shape = Area of rectangle 1 + Area of rectangle 2 + Area of rectangle 3

Area of composite shape = 36 m² + 30 m² + 45 m² = 111 m²

the correct functions are

h(x) = 3x + 2  

g(x) = 2^x

step-by-step explanation:

i proceed to calculate the different values ​​of k (x)

case 1)  k(x) = g(x) ∘ h(x)

g(x) ∘ h(x)=g(h(x))

k(x) = [2]^[3x + > is the option  4. k(x) = 2^(3x + 2 )

case 2)  k(x) = g(x) + h(x)

k(x) = [2^x]+[3x + 2]=2^x+3x+> is the option  1.) k(x) = 2^x + 3x + 2

case 3)k(x) = h(x) ÷ g(x)

k(x) =  [3x + 2]/[2^x]=3x/(2^x)+2/(2^x)=3x*(2^-x)+2^(1-x)

is the option  3.)   k(x) = (3x)2^(-x) + 2^(-x + 1 )

case 4)k(x) = g(x) - h(x)

k(x) =  [2^x]-[3x + 2]=2^x-3x-> is the option  2.) k(x) = 2^x - 3x - 2 

case 5)  k(x) = g(x) × h(x)

k(x) = [2^x]*[3x + > is the option  5.) k(x) = 2^x(3x + 2)

case 6)k(x) = h(x) ∘ g(x)

h(x) ∘ g(x)=h(g(x))

k(x)=3*[2^x]+> is the option  6. k(x) = 3(2^x) +2

the answer would be 1 1/72

step-by-step explanation:

you can rewrite the equation by separating the parts and then solving individually:

10-9=1

1/8 - 1/9=

find l c d and then combine:

1 1/72