An object is launched from a platform. Its height in meters, x seconds after the launch, is modeled by −3(x+4)2+108. After how many seconds does the object reach the max. height? What is the max. height?

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step-by-step explanation:

x^(1/6) · x^(1/6) · x^(1/6)   ·x^(1/6) = x^(4/6)   since we add the exponents

4/6 can be simplified to 2/3

the simplified form is x^(2/3)

1. 3. can also be expressed as (22/7)

2. -4.5

3. 3.6

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