Why am I trying to make the equation true? And why is there no solution? Solve 4 - (3 - x) = x + 5 for x.
SOLUTION
4-(3 - x) = x + 5
4 - 3+x= x + 5
x + 1 = x + 5
1 = 5
“No value of x makes this equation true. It is an example of an equation with no solution.”

there are none alejchskw

shift 4 units up, and 1 unit left.

it will translate f(x) = 3^x to g(x) = 3^(x+1) + 4

c.

step-by-step explanation:

she should of added 9^2 and 12^2. that is because it is a^2+b^2=c^2. c^2 is the hypotenuse and should always be bigger than the other two numbers. which is why she should of added 9 squared and 12 squared together instead of 15 squared.