37) The endpoint of the diameter in circle 0 are (-2,5) and (6,5), find the equation of the circle in standard form

(x-2)^2+y^2=16

Step-by-step explanation:

If the center of the circle is (h,k) and the radius is r, then the equation of a circle is (x-h)^2+(y-k)^2=r^2 (with the Pythagorean theorem)

So, the center of this circle 0 is (2,0) and the radius is 4. Thus, the equation is (x-2)^2+y^2=16

b

step-by-step explanation:

given

- 2 (3x + 12y - 5 - 17x - 16y + 4 )

simplify the parenthesis by collecting like terms

= - 2 (- 14x - 4y - 1) ← distribute the parenthesis by - 2

= 28x + 8y + 2 → b

step-by-step explanation:

x^2 -12x + 36 + y^2 = 36

x^2 + y^2 = 12x

r^2 = 12rcos(theta)

r = 12 cos(theta)