Show Intro/Instructions A wire 15 centimeters long is cut into two pieces. The longer piece is 3 centimeters longer than
the shorter piece. Find the length of the shorter piece of wire.

Let the length of the 2 pieces = L and S

Let L = the longer piece and S = the shorter piece

A wire 26 cm is cut into 2 pieces.  This equates toL + S = 26

The longer piece is 6 cm longer than the shorter piece.  This equates toL = 6 + S.  Substitute this equation into the first one, you get

L + S = 26

6 + S + S = 26

2S = 20

S = 20/2 = 10 cm

L = 6 + S = 6 + 10 = 16 cm

To confirm, L + S = 26

16 + 10 = 26!

Hope the above was helpful.

Step-by-step explanation:

figure c

step-by-step explanation:

hope this .

(b) 240

step-by-step explanation:

first, we use the pythagorean formula using the given side lengths to find x. then we use x to find the side lengths. then we add the side lengths to find the perimeter.

pythagorean theorem formula:

a^2 + b^2 = c^2

(x - 20)^2 + (x - 40)^2 = x^2

x^2 - 40x + 400 + x^2 - 80x + 1600 = x^2

x^2 -120x + 2000 = 0

(x - 100)(x - 20) = 0

x - 100 = 0 or x - 20 = 0

x = 100 or x = 20

we see that the solution x = 20 must be discarded because it will give a negative side length and a side length of 0. the only valid solution is x = 100.

perimeter = sum of the lengths of the sides

perimeter = x + x - 20 + x - 40

perimeter = 3x - 60

replace x with 100.

perimeter = 3(100) - 60

perimeter = 300 - 60

perimeter = 240