A bouncy ball is thrown into the air. The height of the bouncy ball above ground can be represented by the function h(t)=-16t^2+46t+6 where h is the height (in feet) of the ball above the ground, and t is the time (in seconds) that has passed since the ball was thrown. How many seconds will it take the ball to reach the ground?

3,000,540

step-by-step explanation:

step-by-step explanation:

step-by-step explanation:

let's call the solutions x₁ = (5 - 2√7)/3 and x₂ = (5 + 2√7)/3

then the equation is (x-x₁)(x-x₂) = 0

if you fill that in you get a lot of numbers which you can recognize as ax²+bx+c=0.

step-by-step explanation:

you can see that a=1 (there is just an x²)

b = (-5 -2√7 + 2√7 - 5)/3 = -10/3

c = -2√7)/3 ) * (-5+2√7)/3) = -1/3

so your answer is 3x^2 – 10x – 1 = 0