You roll a fair six-sided die. What are the chances the die shows an odd number or a number greater than one?​

4/3

Step-by-step explanation:

Out of the six sides 3 are odd and there's 5 numbers greater than 1. Basically these turn to the fractions 3/6 and 5/6 (these fractions stand for the probability they get rolled on this die).

Since the question says OR and not AND you add these fractions!

3/6 + 5/6 = 4/3

(a) {a₁, a₁r, a₁r², … a₁rⁿ⁻¹, …}

(b) $59 398

step-by-step explanation:

(a) the annual sequence of profits

aₙ = a₁rⁿ⁻¹

the model for the sequence of profits is {a₁, a₁r, a₁r², … a₁rⁿ⁻¹, …} .

(b) profit after 15 yr

  a₁ = $ 30 000

  r = 1.05

a₁₅ = 30 000 × 1.05¹⁴

a₁₅ = 30 000 × 1.979 93

a₁₅ = $59 398

the profit in year 15 will be $59 398.

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step-by-step explanation: