2aa−1
2a2a−1
2a−1
Mathematics, 07.06.2021 19:50 plshelpme53
Multiply.
(a−4)(a+3)a2−4a⋅2a2(a+3)(a−1)
2aa−1
2a2a−1
2a−1
2aa+1
Answers: 1
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You know the right answer?
Multiply.
(a−4)(a+3)a2−4a⋅2a2(a+3)(a−1)
2aa−1
2a2a−1
2a−1
2aa−1
2a2a−1
2a−1
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