For each sequence, find the first 4 terms and the 10th term.
a) 12-n
B 5 - 2n

Solution given:

a.

tn=12-n

1 st term =12-1=11

2nd term =12-2=10

3rd term=12-3=9

4th term=12-4=8

10th term=12-10=2

b.

tn=5-2n

1st term=5-2*1=3

2nd term=5-2*2=1

3rd term=5-2*3=-1

4th term=5-2*4=-3

10th term=5-2*10=-15

(a) Solution

T(n) = 12 - n

T(1) = 12 - 1 = 11

T(2) = 12 - 2 = 10

T(3) = 12 - 3 = 9

T(4) = 12 - 4 = 8

T(10) = 12 - 10 = 2

(b) Solution

T(n) = 5 - 2n

T(1) = 5 - 2 = 3

T(2) = 5 - 4 = 1

T(3) = 5 - 6 = -1

T(4) = 5 - 8 = -3

T(10) = 5 - 20 = -15

step-by-step explanation:

hjkj

answer: c, the green line

step-by-step explanation:

there is no black line, eliminate b.

simple interest implies periodic payments, but the red line shows no payments, eliminate d.

simple interest has equal payments. if paid say every day, the graph is about a straight line (actually a stairstep).

the yellow line is not straight, eliminate a.

check: the green line is straight, answer is c.

simple interest with positive interest rate gives a straight line sloping up to the right. green line:

g(t) = $100 + ($200-$100) ÷ (20 years) × (t years)

= $100 + (4%/year) × ($100)(t years)

incidentally, the yellow line curving upward represents continuously compounded interest

y = $100 × 2^(t years / (14 assuming the yellow line hits $200 at 14 years. 2^0 is 1, so y(0) = $100; 2^(14/14) is 2, so y(14) = $200.