A marine biologist wanted to construct a t interval to estimate the mean weight of marine otters using 98% confidence. They took a random sample of n = 8 marine otters to measure their weights. These weights were roughly symmetric with a mean of 2 = 4.5 kg and a standard deviation of sx = 1.1 kg. What critical value t* should they use?

CI 98 %  =  ( 3.332  ;  5.668 )

t(c)  =  2.9979

Step-by-step explanation:

Confidence Interval  CI  98 %   then  α  =  2 %   α  =  0,02    α/2  =  0.01

Sample information:

Sample size    n  =  8

sample mean     x  =  4.5

standard deviation of sample    s  =  1.1 kg

degree of freedom     df  =  n  -  1     df  =  8  -  1    df  =  7

With    α/2  0.01  and  df  =  7 from t-studente table we find   t(c)

t(c)  =  2.9979

CI 98 %  =  (   x  ±  t(c) * s/√n )

CI 98 %  =  (  4.5  ±  2.9979 *  1.1/ √8 )

CI 98 %  =  (  4.5  ±  3.2976/2.8228 )

CI 98 %  =  (  4.5  ± 1.168 )

CI 98 %  =  ( 3.332  ;  5.668 )

answer: answer is c!

ok i got to organize the

3/15 and 12/55

3*

aha

3*4 equals 12 but not

a: no

b:

8/24 12/35

no

gautie

it's c

5/18 = 25/90

5*5=25

18*5 = 90

hope that you!

one more happy customer!

< 3

step-by-step explanation:

simplifying

5(x + -6) = 2(x + 3)

reorder the terms:

5(-6 + x) = 2(x + 3)

(-6 * 5 + x * 5) = 2(x + 3)

(-30 + 5x) = 2(x + 3)

reorder the terms:

-30 + 5x = 2(3 + x)

-30 + 5x = (3 * 2 + x * 2)

-30 + 5x = (6 + 2x)

solving

-30 + 5x = 6 + 2x

solving for variable 'x'.

move all terms containing x to the left, all other terms to the right.

add '-2x' to each side of the equation.

-30 + 5x + -2x = 6 + 2x + -2x

combine like terms: 5x + -2x = 3x

-30 + 3x = 6 + 2x + -2x

combine like terms: 2x + -2x = 0

-30 + 3x = 6 + 0

-30 + 3x = 6

add '30' to each side of the equation.

-30 + 30 + 3x = 6 + 30

combine like terms: -30 + 30 = 0

0 + 3x = 6 + 30

3x = 6 + 30

combine like terms: 6 + 30 = 36

3x = 36

divide each side by '3'.

x = 12

simplifying

x = 12

this should .