In ΔPQR, r = 9 inches, p = 6.6 inches and ∠Q=6°. Find the area of ΔPQR, to the nearest 10th of a square inch

2.8 square inches

Step-by-step explanation:

Area of the triangle PQR = 1/2 rp sin <Q

Given

r = 9in

p = 6.6in

<Q =6°

Substitute into the formula;

Area of the triangle PQR = 1/2 * 9 * 6 sin6°

Area of the triangle PQR = 9 * 3 sin6°

Area of the triangle PQR  = 27 sin6°

Area of the triangle PQR = 27(0.1045)

Area of the triangle PQR = 2.82

Hence the area to the nearest 10th of a square inch is 2.8 square inches

i get you, what you should do is think of the positive things that would come out of it. it will make yours parents proud and raise your grade. you should always try and if you can't focus tell the teacher.