Jason wants to know the percentage of M & M's that are green. He chooses a sample of 30 M & M's from a bag, and 3 of them are green. What is the margin of error of his experiment (round to 4 decimal places)? .1074 .1074 .9845 .9845 .1235 .1235 .8824

The margin of error of his experiment is of 0.1074.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of , and a confidence level of , we have the following confidence interval of proportions.

In which

z is the z-score that has a p-value of .

The margin of error is of:

30 M & M's from a bag, and 3 of them are green.

This means that

Standard 95% confidence level

So , z is the value of Z that has a p-value of , so .

Margin of error:

The margin of error of his experiment is of 0.1074.

imma say 16%. sorry if its wrong. i'm doing the same stuff right now

step-by-step explanation: