A 4.5 m long pipe rests against a 2 m high tank. One end of the pipe is on the ground
3 m from the base of the tank. How much
of the pipe overhangs the tank?
4.5 m
Bm
3 m

help me please lol

0.89 m is the answer

Step-by-step explanation:

the wall, the ground and portion of pipe form a right angle triangle with pipe portion being the hypotenuse.

for a right triangle

here we have base = 3m and height = 2m.

thus

portion of pipe overhanging = 4.5 - sqrt (13)

= 4.5 - 3.61

= 0.89 m

step-by-step explanation:

0

(b) 240

step-by-step explanation:

first, we use the pythagorean formula using the given side lengths to find x. then we use x to find the side lengths. then we add the side lengths to find the perimeter.

pythagorean theorem formula:

a^2 + b^2 = c^2

(x - 20)^2 + (x - 40)^2 = x^2

x^2 - 40x + 400 + x^2 - 80x + 1600 = x^2

x^2 -120x + 2000 = 0

(x - 100)(x - 20) = 0

x - 100 = 0 or x - 20 = 0

x = 100 or x = 20

we see that the solution x = 20 must be discarded because it will give a negative side length and a side length of 0. the only valid solution is x = 100.

perimeter = sum of the lengths of the sides

perimeter = x + x - 20 + x - 40

perimeter = 3x - 60

replace x with 100.

perimeter = 3(100) - 60

perimeter = 300 - 60

perimeter = 240