Show that the sum of the measures of the external angles of any polygon is 360°. [ HINT:- Draw three different polygons like a triangle, quadrilateral, pentagon. Extend each side, then measure the exterior angles from there. Finally, find the sum of measures of all exterior angles of each polygon.]

basically get a shape

eg we will work with triangles,, add angles to the inside,, ensuring they add up to 180 (because angles in a triangle add up to 180)

now that we have the angles,, extend each side with a line to show the exterior angles.

we know that angles on a line add up to 180,, so to find the external angle,, we can use our internal angle

you would use:

[ 180- internal angle]

do this for all external angles

add all your answers together,, should equal to 180

answer: a. 74

step-by-step explanation:

it shows divided evenly, so add the 37+37 = 74

(sin 42)/31. = sinx)/37

sinx = 37 (sin42)/31

= 37× 0.66/31 = 0.787

x= 51.9

other angle opposite to y = 180-51.9-42

= 180- 93.9 =86.1

so

sin42)/31 = sin 86.1)/y

0.021 = 0.997 /y

y= 0.997/0.021 =47.47