Volume of square based pyramid is 1568 cm3 and half of the length of the side of the base is 7cm. Calculate the area of triangular faces of pyramid.
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1393.84

Step-by-step explanation:

since the formula for a square base pyramid is a^2×h/3

we can find out the height for the pyramid by dividing the a^2×h/3 by a^2 =h/3

1568/7^2=32 since 32 = h/3 we multiply by 3 to find the height which = 96

now that we have the height we usee the pathagorean Therom to find the height of one of the face triangles

so 96^2+3.5^2=L^2 so L =96.06

so now that we have all we need

the surface area of the square at the bottom of the pyramid is 7×7

the surface area of the triangles are 96.06 ×7/2 since the area of a triangle is h×b/2

since there are 4 triangles and on square 49+4(96.06×7/2)= 1393.84

x = -2

y = 848

step-by-step explanation:

plug in the numbers

i dont know

step-by-step explanation: