City A is due north of City B. Find the distance between City A ​( north​ latitude) and City B ​( north​ latitude). Assume that the radius of Earth is 3960 miles. The distance between City A and City B is ___miles.

Can someone help?! Show me step by step how this is done that I can understand it better.

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Explanation:

The notation means "47 degrees, 4 minutes". The "minutes" isn't referring to a time value, but instead they are arc minutes. If we divide one degree into 60 equal pieces, then we form 60 arc minute slices. So in a sense, we are using a round analogue clock to help connect the two ideas.

We can convert to purely degrees through using this formula here

So,

and similarly,

Now subtract the two results we got

47.06667-22.76667 = 24.3

The angular distance between the two cities is 24.3 degrees. By "angular distance" I basically mean how far you need to rotate your viewing angle when looking from city A to city B. Imagine that you're able to be situated at the center of the earth.

The circumference of the earth is

C = 2*pi*r

C = 2*pi*3960

C = 24,881.4138164311

which is approximate and the units are in miles. We multiply by the fraction 24.3/360 to find the arc distance along the curve that corresponds to the angle 24.3 degrees. This is because we don't want the whole circumference, but just a small fraction of it.

So (24.3/360)*24,881.4138164311 = 1,679.4954326091

This rounds to 1679

The distance between the two cities is about 1679 miles.

since the airplane is moving with constant speed then the distance travelled can be calculated by x=u*t

in km/h would be:

x=640*3.5=2.240 km

in m/s would be:

u=640 km/h= 640.000 m/h =640.000/ 3600 m/s =177.8 m/s

t= 3.5 h= 3.5 * 3600 s=12.600 s

then x=u*t= 177.8*12.600= 2.240.280 m

10.4 inches

step-by-step explanation:

2x2x2.6