Given that 2 sec?0 – tan²0 = p. show that cosec²theta= p-1/p-2,p≠2

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Step-by-step explanation:

2/cos^2(theta) - sin^2(theta)/cos^(theta) = p

(2 - sin^2(theta) ) / cos^2(theta) = p

cos^2(theta) = 1 - sin^2(theta)                    Relationship between sines and cosines

2 - sin^2(theta)/ (1 - sin^2(theta) ) = p        Everything is now in terms of sines

sin^2 (theta) = 1 / csc ^2 (theta)                 sin^(theta) = 1/csc(theta)

2 - 1/csc^2(theta)                                        Make Left over csc(theta)

       =  p

1 - 1/csc^2(theta)

2 csc^2(theta) - 1

csc^2(theta)

   = p         Cancel out denominators (csc^2(theta))

csc(theta)  - 1

csc^2(theta)

2 csc^2 (theta) - 1

     = p              Multiply both sides by csc^2(theta) - 1

csc^2(theta) - 1

2csc^2(theta) - 1 = p*csc^2(theta) - p   Collect csc^2(theta) on the left, p on the right.

csc^2(theta) (2 - p)  = 1 - p

csc^2(theta) = (1 - p)/(2 - p)

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step-by-step explanation:

correct choice is b

step-by-step explanation:

when you calculate the average rate of change of a function, you are finding the slope of the secant line between the two points. for the function the average rate of change from point to point can be calculated as

to find the average rate of change from day 2 to day 10, note that at day 2, 8 houses were sold, so a(2,8) and at day 10, 2 houses were sold, so b(10,2). thus,