Write one digit on each side of 73 to make a four digit multiple or 36. How many different solutions does this problem have? And what are they.

73 u have to add any digit either at right or left therefore

73+11=

them multiply by 36

73×36

Addison and multiplication is t a e answer

There are two solutions to the problem.

The numbers are 6732 and 2736.

Step-by-step explanation:

36 = 4*9

The four digit number must be divisible by 4 AND by 9.

The last two digits must be divisible by 4.  So only 2 and 6 are possible.

X732, X736.

X must be such that the four-digit number is divisible by 9.

7+3+2=12, so a 6 to make the sum of digits = 18, hence divisible by 9.  So 6732 is divisible by 36.

7+3+6 = 16, so a 2 to make 2736 whose sum of digits = 18, hence the four digit number is divisible by 9.  So 2736 is divisible by 36.

There are two solutions to the problem.

The numbers are 6732 and 2736.

hi,

6x times 4 is 24x and 5 times 4 is 20, so the answer is 24x+20.

hope this and for a little humor i am groot.

nada

step-by-step explanation: