Find the equation of the line that passes through (1,2) and is perpendicular to y=2x+3
Leave your answer in the form
y=mx+c

Step-by-step explanation:

Hey there!

The equation of line which passes through the point (1,2) is (y-2) = m1(x-1)(i)

The another given equation is y= 2x + 3(ii)

Comparing the equation (ii) with y= mx+c we get;

Slope (m2)= 2.

As per the condition of perpendicular lines, m1*m2 = -1.

m1*2 = -1

Therefore, m1 = -1/2.

Keeping the value of m1 in equation (i) we get;

(y-2) = -1/2(x-1)

y - 2 = -1/2x +1/2

y = -1/2 X + 1/2 + 2

Therefore, the required equation is y = -1/2 X + 5/2.

Hope it helps!

it should be a and d. lmk if i'm wrong xd

part 1 answer = 8

part 2 answer = 72

step-by-step explanation:

part 1 explanation = add all of the numbers, then divide by how many numbers you have. so, 200/25 = 8.

part 2 explanation = not gonna lie, this is hard to explain, so just google how to do it.