Students in a marine biology program built underwater drones. The students were split into two groups, and each group designed and built its own drone. During a recent round of testing, they modeled the path of each drone using these
functions, where x is the horizontal distance from the launch site, in miles, and d(x) is the depth below the surface of the
water, in meters.
Voyager: d(x) = 0.25(x – 35)^2 – 225
Pioneer: d(x) = 0.3(x – 32)^2
- 270
Use the custom button to graph the functions and determine the depth of each drone at its lowest point.

let's add {f(x)=x+1}f(x)=x+1 and {g(x)=2x}g(x)=2x together to make a new function.

f(x)+g(x) =(x+1)+(2x)=x+1+2x=3x+1

let's call this new function hh. so we have:

{h(x)}={f(x)}+{g(x)}{=3x+1}h(x)=f(x)+g(x)=3x+1

we can also evaluate combined functions for particular inputs. let's evaluate function hh above for x=2x=2. below are two ways of doing this.

method 1: substitute x=2x=2 into the combined function hh.

h(x)

h(2)

​    

=3x+1

=3(2)+1

=7

​ since h(x)=f(x)+g(x)h(x)=f(x)+g(x), we can also find h(2)h(2) by finding f(2) +g(2)f(2)+g(2).

first, let's find f(2)f(2):

f(x)

f(2)

​    

=x+1

=2+1

=3

​  

now, let's find g(2)g(2):

g(x)

g(2)

​    

=2x

=2⋅2

=4

​  

so f(2)+g(2)=3+4=\greend7f(2)+g(2)=3+4=7.

notice that substituting x =2x=2 directly into function hh and finding f(2) + g(2)f(2)+g(2) gave us the same answer!

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step-by-step explanation:

2 over 5 and 4 over 15

don’t know last one sorry

step-by-step explanation:

its a i did it myself

step-by-step explanation: