What is an equation of the line that passes through the point (-5,-2)and is parallel to the line x-y=5?

Step-by-step explanation:

Hi there!

What we need to know:

1) Determine the slope (m)

Rearrange this given equation into slope-intercept form. This will make it easier for us to identify the slope.

Subtract x from both sides of the equation

Divide both sides by -1 to isolate y

Now, we can identify clearly that the slope of this line is 1. Because parallel lines have the same slopes, a line parallel to this one would also have a slope of 1. Plug this into :

2) Determine the y-intercept (b)

Plug in the given point (-5,-2)

Add 5 to both sides

Therefore, the y-intercept of the line is 3. Plug this back into :

I hope this helps!

ad = ae + ed = y + 7

similar triangles therefor

ac/ab = ad/ae

6/4 = (y + 7) / y

cross multiply

6y = 4(y + 7)

6y = 4y + 28

2y = 28

y = 14

step-by-step explanation: