What is the sum of the geometric series in which a1 = 3, r = 4, and an = 49,152? Hint: an = a1(r)n − 1, where a1 is the first term and r is the common ratio.

Hint: cap s sub n equals start fraction a sub one left parenthesis one minus r to the power of n end power right parenthesis over one minus r end fraction comma r does not equal one comma where a1 is the first term and r is the common ratio.

Sn = −65,535
Sn = 16,383
Sn = 13,120
Sn = 65,535