Calculate the perimeter of a triangle with vertices (-9,-1)(-1,-1)(6,5)

34.79 (length units)

Step-by-step explanation:

To calculate the perimeter, we need to add up all the sides.

We use Pythagoras Theorem to calculate the side, taking the differences of the coordinates of the vertices, squaring and taking square-root.

Side 1:  between (-9, -1) and (-1,-1)

Differences in coordinates: 8,0 => length = 8

side 2: between (-1,-1), (6,5)

differences in coordinates: 7,8, => length = sqrt(7^2+8^2) = sqrt(113)

side 3: between (6,5), (-9,-1)

differences in coordinates: 15,6 => length = sqrt(15^2+6^2) = 3sqrt(29)

Perimeter

= 8 + sqrt(113) + 3sqrt(29)

= 8 + 10.63 + 16.16

= 34.7856

the answer will be the last one

x =±sqrt(1/3)

step-by-step explanation:

x+4/6x=1/x

multiply each side by 6x to get rid of the fractions

6x*(x+4/6x)=1/x*6x

distribute

6x^2 +4 = 6

subtract 4 from each side

6x^2 +4-4 = 6-4

6x^2 =2

divide by 6

6x^2/6 = 2/6

x^2 = 1/3

take the square root of each side

sqrt(x^2) = ±sqrt(1/3)

x =±sqrt(1/3)