A lot is 60 m by 39 m. A house 28 m by 9 m is built on the lot. How much area is left over?
House
9 m
39 m
28 m
60 m
The area left over is ?

Area of lot = 60×39 = 2340 m²

Area of house = 28×9 = 252 m²

Area left over is = Area of lot - Area of house = 2340-252= 2088 m²

Step-by-step explanation:

area of the lot = length × breadth

= 60 × 39

= 2340 m²

area of the house = length × breadth

= 28 × 9

= 252 m²

area of the leftover portion = 2340 - 252

= 2088 m²

the polynomial is a perfect square trinomial of the form a^2-2ab+b^2:

option a. true

step-by-step explanation:

9x^2-12x+4

comparing with the form a^2-2ab+b^2

1.) a^2=9x^2

solving for a: square root both sides of the equation:

sqrt(a^2)=sqrt(9x^2)

a=sqrt(9) sqrt(x^2)

a=3x

2.) b^2=4

solving for b: square root both sides of the equation:

sqrt(b^2)=sqrt(4)

b=2

to be a perfet square trinomial 2ab must be equal to 12x. let's check:

2ab = 2 (3x) (2)

2ab = 12x

correct

the real question is why is this guys last name heavyfoot

step-by-step explanation: