Find the center and radius of the circle whose equation is x 2 + y 2 - 6x - 2y + 4 = 0 (3,1), r = /6
(-3,-1), r = /6
(3,1) r = 6
(9,1), r = 36

Solution given:

the equation of a circle is:

x²+y²-6x-2y+4=0

x²-2*x*3+3²+y²-2y+1²-1²+4=0

(x-3)²+(y-1)²=9+1-4

(x-3)²+(y-1)²=6

comparing above equation with

(a-h)²+(y-k)²=r²

we get

centre (h,k)=(3,1)

radius=√6

option first

(3,1), r = √6 is a required answer.

(3,1), r = √6 is a required answer.

Step-by-step explanation:

correct choice is b

step-by-step explanation:

when you calculate the average rate of change of a function, you are finding the slope of the secant line between the two points. for the function the average rate of change from point to point can be calculated as

to find the average rate of change from day 2 to day 10, note that at day 2, 8 houses were sold, so a(2,8) and at day 10, 2 houses were sold, so b(10,2). thus,