Quandrilateral ABCD is inscribed in a circle. What is the measure of angle A? A=(2x-40)B 116 C D=x what is the measure of angle A

angle A = 88°

Step-by-step explanation:

Given: inscribed quadrilateral ABCD

(recall that inscribed quadrilaterals have opposite angles supplementary.

A=2x-40

B=116

D=x

From inscribed quadrilateral,

B+D=180 => 116+x = 180 => x=64

A=(2x-40) = 2*64-40 = 88°

(C = 180-88 = 92°)

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