Suppose a normal distribution has a mean of 48 abd a standard deviation of 5. What is the probability that a data value is between 48 and 52?

P(48<x<52) = 0.2881

Step-by-step explanation:

P(48<x<52) = normalcdf(lower,upper,µ,σ) = normalcdf(48,52,48,5) ≈ 0.2881

Therefore, the probability that a data value is between 48 and 52 is 0.2881, or about a 28.81% chance of occurrence.

24

step-by-step explanation:

if it takes 8 pounds to make 12 divide 12 by 8 and you get 1.5, 1.5 x 16 = 24