Find the zeros of y = x2 - 6x – 4 by completing the square. O A. x = 3 + 5
B. X = +3
C. X = 3 + 13
D. x.-3113

√13 + 3 = x

-√13 + 3 = x

Step-by-step explanation:

y = x² - 6x - 4

0 = x² - 6x - 4

0 + 13 = x² - 6x - 4 + 13

13 = x² - 6x + 9

13 = (x-3)²

±√13 = x-3

±√13 + 3 = x

√13 + 3 = x

-√13 + 3 = x

the transverse axis of a hyperbola is the line that contains the two vertices and the two focuses.

in this example (hyperbola of equation x^2/2 - y^2/4 = 1), the transverse axis is the  x-axis  . 

step-by-step explanation:

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step-by-step explanation: