Hi please help will mark brainliest Charlie and Andie solve this problem in two different ways: A family of 6 spent $74 at the movie theater.
They bought $26 worth of snacks and a ticket for each family member.
What is the price of each ticket if all tickets are the same price​

8$

Step-by-step explanation:

since it was 26$ worth of snacks, first subtract 74 from 26

74-26= 48$ left

from this 48$, they bought tickets, therefore price for one ticket= 48/6=8$

therefore each ticket cost 8$

hope this helps!

Step-by-step explanation:

subtract/divide/a variable

credit: edgarandres9741

source:

the answer   is 200

step-by-step explanation:

this is a problem about poisson probabilities.   i don't know if you've

already studied poisson distributions, or if you have a place to look

to read more about the subject.  

here's how you can see a poisson distribution coming.   when there are

a lot of events that may happen at any time (or any place), and when

you're counting how many of them happen at a particular time (or a

particular place), and each event is independent of the others, then

the result is a poisson distribution.   this is roughly true for the

chocolate chips; one chip being in a cookie has only a small effect on

the probability that another chip will be in the cookie.

once you know you have a poisson distribution, you know a lot.   there

is only one parameter to a poisson distribution, so if you know the

mean, you know everything.   the form of the distribution is

  probability of n chips = {[e^(-x)]*(x^n)} / (n! )

answer: what is the question you're trying to ask?

step-by-step explanation: