Please show your work

from pethagoeraous trick

Ac²=Ab+Bc²

then 10²= 6²+xx

=> 64= x²

so x= 8 ans

so

8

Step-by-step explanation:

This can be solved using Pythagoras theorem, which is a² + b² = c², in which c is the hypotenuse (the longest side) and a and b are the two other sides. This only works for right-angled triangles, which we can see it will work for this question as there is a right angle marked by a square.

To find x, we must substitute the values in so 6² + x² = 10², which simplifies to the following:

36+x²=100.

Then we must take away 36 from both sides, leaving x²=64. To find x, find the square root of both sides, leaving x=8

I hope this helps! ;)

x =-.20752

step-by-step explanation:

4^(x+2)=12

4^(x+2)=12

take the log base 4 on each side

log 4 (4^(x+2) = log 4(12)

we know log b(a^y) = y log b (a)

(x+2) log 4(4) = log 4 (12)

x+2 = log 4 (12)

we know   logb c = loga c/loga b

we want to convert to base 10   so a = 10

by default, we do not write the 10   c = 4   and b = 10

log4 10 = log 12/log 4

log4 10 = log 12/ log 4

x+2 = log 12/ log 4

subtract 2 from each side

x +2 -2 = log 12/ log 4 -2

x = 1.79248125 -2

x =-.20752