Find xy if x + y=3, x^2 + y^2 = 5

mark me

Step-by-step explanation:

x+y=3

x=3-y

putting the value of x

in this

x²+y²=5

(3-y) ²+y²=5

9-6y+y²+y²=5

2y²-6y+9-5=0

2y²-6y+4=0

2y²-4y-2y+4=0

2y(y-2)-2(y-2)=0

(2y-2) (y-2) =0

2y-2=0 or y-2=0

y=1 or y=2

so x=2 or 1

so x×y=2×1 or 1×2=2

I HOPE THIS WILL HELP YOU MARK ME BRAINLIEST

step-by-step explanation:

use pothagarean therom

a^2+b^2=c^2 so first ac

acm is a right triangle because c= 90°

and am (the hypotenuse or c) =16+9 =25

but there is not enough info we need another angle or side length