Which conversions from scientific notation to standard notation are true? Select the four correct answers

The options are missing, so i have attached them.

options B, E, G & H are correct.

Step-by-step explanation:

A) We are given;

1.71 × 10³ = 0.00171

For this conversion, the exponent attached to 10 is positive. This means we will have to move the decimal point to the right of 1.71 three times because the exponent is 3.

Thus, the proper conversion is;

1.71 × 10³ = 1710

B) We are given;

8.05 × 10^(5) = 805000

For this conversion, the exponent attached to 10 is positive. This means we will have to move the decimal point five times to the right of 8.05 because the exponent is 5.

Thus, the proper conversion is;

8.05 × 10^(5) = 805000

C) We are given;

2.4 × 10⁴ = -24000

For this conversion, the exponent attached to 10 is positive. This means we will have to move the decimal point four times to the right of 2.4 because the exponent is 4.

Thus, the proper conversion is;

2.4 × 10⁴ = 24000

D) We are given;

8.25 × 10^(-3) = -8250

For this conversion, the exponent attached to 10 is negative. This means we will have to move the decimal point three times to the left of 8.25 because the exponent is -3.

Thus, the proper conversion is;

8.25 × 10^(-3) = 0.00825

E) We are given;

7.09 × 10^(-6) = 0.00000709

For this conversion, the exponent attached to 10 is negative. This means we will have to move the decimal point six times to the left of 7.09 because the exponent is -6.

Thus, the proper conversion is;

7.09 × 10^(-6) = 0.00000709

F) We are given;

3.99 × 10^(5) = 300,099

For this conversion, the exponent attached to 10 is positive. This means we will have to move the decimal point five times to the right of 3.99 because the exponent is 5.

Thus, the proper conversion is;

3.99 × 10^(5) = 399,000

G)We are given;

8 × 10^(7) = 80,000,000

For this conversion, the exponent attached to 10 is positive. This means we will have to move the decimal point seven times to the right of 8 because the exponent is 7.

Thus, the proper conversion is;

8 × 10^(7) = 80,000,000

H) We are given;

1.03 × 10^(-4) = 0.000103

For this conversion, the exponent attached to 10 is negative. This means we will have to move the decimal point four times to the left of 1.03 because the exponent is -4.

Thus, the proper conversion is;

1.03 × 10^(-4) = 0.000103

Looking at all the options as well as the proof I got, only options B, E, G & H are correct.

29 mil

step-by-step explanation:

step-by-step explanation: given equation a = h(b 1+b 2)

also we are given values of a, h and b 1 as :

a = 16, h = 4, and b 1 = 3.

in order to solve it for b 2, we need to plug the given values of   a, h and b 1 .

therefore, plugging values of   a, h and b 1   in given equation, we get

16 = 4( 3 + b 2)

first dividing both sides by 4, we get

4 = 3 + b 2

subtracting 3 from both sides, we get

4 -3 = 3 -3 + b 2

1 = b 2.