The varsity soccer team has 20 players. Three of the players are trained to be goalies while the remaining 17 can play any position. Only 11 of the players can be on the field at once.

A.) combination

B.) 167,960 ways

C.) 58,344 ways

Step-by-step explanation:

A.)

Choosing 11 players out of 20 available is a cbinationtuon problem simply because the order of choice of the 11 players does not matter on this scenario.

B.)

Here, the coach wants to select her 11 from all available 20:

We apply the combination formula :

nCr ; where ; n = 20 ; selection, r = 11

nCr = n! / (n-r)!r!

20C11 = 20! / 9!11!

20C11 = 167,960

C.)

1 goalie 10 players

1 goalie is selected from the 3 available goalies AND 10 players from the 17 available players :

This gives :

3C1 * 17C10

3C1 = 3

17C10 = 19,448

3C1 * 17C10 = 3 * 19448

= 58,344 ways

0.84 dang lotta people are looking for this lol or if you round up its 1 but the overall answer to that is 0.84

step-by-step explanation:

dc=6 square root of 3 and ac is 12 square root 3

c and d

step-by-step explanation:

square root of 3/2 = 18/c

cross multiply to get 18*2=√3*c

36/√3 * √3/√3 = c

c= 36*√3/3

c=12√3