There are 3 oranges, 8 peaches, and 4 apples in a fruit basket. David selected one piece of fruit at random. He was hungry and ate that fruit. He then selected a second piece of fruit. What is the probability that he selects two peaches?

Probabilty[First and second fruit is peach without replacement] = 0.267 (Approx.)

Step-by-step explanation:

Given:

Number of oranges = 3

Number of peach = 8

Number of apple = 4

Find:

Probabilty[First and second fruit is peach without replacement]

Computation:

Probablity of an event = Number of favourable outcomes / Number of outcomes

Probabilty[First fruit is peach] = 8 / [3 + 8 + 4]

Probabilty[First fruit is peach] = 8 / 15

Probabilty[Second fruit is peach] = [8-1] / [3 + 8 + 4 - 1]

Probabilty[Second fruit is peach] = 7 / 14

Probabilty[Second fruit is peach] = 1 / 2

Probabilty[First and second fruit is peach without replacement] = Probabilty[First fruit is peach] x Probabilty[Second fruit is peach]

Probabilty[First and second fruit is peach without replacement] = [8/15][1/2]

Probabilty[First and second fruit is peach without replacement] = 8 / 30

Probabilty[First and second fruit is peach without replacement] = 0.267 (Approx.)

mark branliest

step-by-step explanation:

.6 is 1/2 of 12

the answer is actually d. i just took the test