Part A This year, water usage has increased by 20% for both regular days and special events.
LAST YEAR'S WATER USAGE:
All regular days - 13,505 gallons
Per special event - 18.5 gallons
Total for the year - 13,616 gallons
Write an equation for the total water usage, U, at the park this year in terms of x, the number of special events the park has hosted.

The total water usage at the park this year, in gallons, U = 16,206 + 22.2·x

Step-by-step explanation:

The given parameters are;

The increase in water usage for both regular days and special event for the current year = 20%

The water usage for last year regular days = 13,505 gallons

The water usage per special event = 18.5 gallons

The total water usage = 13,616 gallons

Therefore, we have;

The water usage for regular days on the current year = 13,505 gallons + (20/100)×13,505 gallons = 16,206 gallons

The water usage per special event for the current year, x = 18.5 gallons + (20/100) × 18.5 gallons = 22.2 gallons

The total water usage, U, at the park this year in terms of 'x', the number of special events the park hosted is given by the sum of the amount of water used on regular days and the product of 'x', and the amount of water used per special event this year as follows;

U = 16,206 gallons + x × 22.2 gallons

∴ The total water usage at the park this year, U = 16,206 + 22.2·x

U=16,206+22.2 ^. x

Step-by-step explanation:

-362

step-by-step explanation:

(12)(4)+2(12)-34(12)+2(12)-3

  \/         \/         \/         \/

  48 +   24 -   408 + 24 - 3

      \   /               \   /

          72     -     432 - 3 = -363

answer: my brother can figure it out, imma go get him so i can answer : ) edit: my brother is sleeping, sorry man

step-by-step explanation: