Factor and find the zeros of the relation. (c.) y = 30x^2 + 44x + 16
(d.) y = 10x^2 +60x + 80

Step-by-step explanation:

c.

y= 30x² +44x +16

factor

y= 2 (15x² +22x +8)

find zeros

15x²+22x+8=0

ax²+bx+c=0

x= (-b±√(b²-4ac))/2a

x= -22±√484-480/30 = -22±2/30 = -11±1/15

there are 2 zeros x= -10/15 ; x= -12/15

d.

y= 10x² +60x +80

factor

y= 10(x²+6x+8) = 10( x+2)(x+4)

finding zeros

x+2 =0 so x= -2

x+4 =0 so x= -4

there are 2 zeros x= -2; x= -4

answer: bearing in mind that a rectangle has a perimeter of length + length + width + width.

step-by-step explanation:

p = perimeter

l = length

x=width

p = 2l + 2x

p = 2(l+x)     < ==== perimeter of the base of the box.