find three consecutive odd integers such that the sum of the last two is 15 less than 5 times the first​

2n + 1 , 2n + 3 , 2n + 5

( 2n + 5 ) + ( 2n + 3 ) = 5 × ( 2n + 1 ) - 15

4n + 8 = 10n + 5 - 15

4n + 8 = 10n - 10

Add both sides 10

4n + 8 + 10 = 10n - 10 + 10

4n + 18 = 10n

Subtract both sides 4n

4n - 4n + 18 = 10n - 4n

18 = 6n

Divide both sides by 6

18 ÷ 6 = 6n ÷ 6

n = 3

Thus that three numbers are :

2(3) + 1 , 2(3) + 3 , 2(3) + 5

6 + 1 , 6 + 3 , 6 + 5

7 , 9 , 11

And we're done

answer: i'm not going to give you the answer, but some hints to work it out.

step-by-step explanation: so, if there is a straight line that means that the line angle is 180°. so we subtract the 2 angle measures provided, (15 and 38) from 180. so the answer is 180 - (38 + 15). (you have to solve the equation)

step-by-step explanation:

1. practice, practice & more practice

2. review errors

3. master the key concepts

do not try to memorise the processes.

4. understand your doubts.

5. create a distraction free study environment

6. create a mathematical dictionary

7. apply maths to real world problems.