Please help i have to finish 15 assignments today including a final exam and i dont know what im doing NO LINKS OR YOU WILL BE REPORTED

(-1,6) ; (-2,11)

Step-by-step explanation:

y= x^2-2x +3

y= -5x + 1

the best way to proceed is substitute the value of y shows in the second equation in the first equation (general rule: substitute the value shows in the linear equation in the quadratic equation)

-5x + 1 = x^2-2x+3

x^2 +3x + 2 = 0

(x+2)(x+1) = 0

x = -2

x = -1

Solution 1

x = -1

y = 5 + 1 = 6

Solution 2

x = -2

y = 10 + 1 = 11

options a,b,c are the right answer.

step-by-step explanation:

a linear parent function is always represented as y = x

if we write this function in the form of y=mx+c

⇒

or  

now if we plot a graph we will find these characteristics:

1) y intercept of the graph is zero so its a straight line passing through origin.

2) as we can see in both the forms of function written, values of x and y may be either positive or negative for the positive slope means points on the graph are either in first quadrant or in third one.

3) it's slope is one.

the answer is y < -3 or   y > 3

-3y > 7 + 2

-3 y > 9

y < -3